PHP实现-计算两个坐标的距离
2018-08-24 11:00 By
"Powerless"
3065
0
2
/**
* 计算两个坐标之间的距离(米)
* @param [array] $from [起点坐标(经纬度)]
* @param [array] $to [终点坐标(经纬度)]
* @return int
*/
private function getDistance($from,$to)
{
sort($from);
sort($to);
$radius=6371393;
$lat1=($from[0]* pi()) / 180;
$lng1=($from[1]* pi()) / 180;
$lat2=($to[0]* pi()) / 180;
$lng2=($to[1]* pi()) / 180;
$stepOne= pow(sin(($lat2-$lat1)/2),2) + cos($lat1) * cos($lat2) * pow(sin(($lng2-$lng1)/2),2);
$stepTwo=2* asin(min(1, sqrt($stepOne)));
return round($radius*$stepTwo);
}
View in WeChat
Others Discussion
-
浏览器访问网站经历的步骤-Html Posted on 2018-11-28 18:48
-
TCP协议的特性 Posted on 2019-04-26 16:46
-
HTTP头中隐藏PHP版本号 Posted on 2021-01-11 16:38
-
Composer 异常 [ErrorException] Posted on 2019-11-25 17:55
-
PHP练习-移动数组内的0到最后并保持其他元素顺序不变 Posted on 2020-08-14 20:32
-
能创建多少个 TCP 连接？ Posted on 2021-08-02 16:00
-
Mysql联合索引的最左前缀匹配原则 Posted on 2018-08-25 15:00
-
PHP没你想的那么差 Posted on 2021-12-17 15:40
评 论